The electrochemical equivalent of a metal is 3.3 × 10⁻⁷ kg per coulomb. The mass of the metal liberated at the cathode when a 3 A current is passed for 2 seconds will be(a) 19.8 × 10⁻⁷ kg(b) 9.9 × 10⁻⁷ kg(c) 6.6 × 10⁻⁷ kg(d) 1.1 × 10⁻⁷ kg
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The mass of 2mcube of steel is 15600 kg.calculate the density of steel in S.I unit .
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Answer:
a) 19.8 × 10⁻⁷kg
Explanation:
Electrochemical equivalent of a metal = 3.3 × 10⁻⁷ kg (Given)
Current across cathode = 3A (Given)
Time of the current = 2 seconds (Given)
This, if R=r -, then as per the equation -
P max = E²/4r
- wherein, the power delivered will be maximum
m = zit
m= 3.3 × 10⁻⁷ × 3 × ²
m= 19.8 × 10⁻⁷
Therefore, a current passed for two seconds across the cathode will be 19.8 × 10⁻⁷kg