Question

the electrode potential of hydrogen electrode is when H3O+ ion concentration is 10^-5 M ​

Answer 1

Answer:

Given:

E = 118.5mV = 118.5 × 10– ³V

We know that,

E cell = 0.0591/n log [ H + ]

Here, N = 1

So,

log |H +| = - 118.5 × 10– ³/ 0.0591

log |H +| = -2.0051

|H +| = 0.01 M

Hope it's helpful for you

Answer 2

The hydrogen ion concentration was calculated as $0.01M$

Explanation:

• The electrode potential  or Ecell of the hydrogen electrode is $-118.5mV$ which is equal to $-118.5$×$10^{-3}$ V

$E_{cell} =\frac{0.0591}{n}log [H^{+}]$  ---------eqn 1

Here n=1 substituting the values in eqn 1

$log[H^{+} ]=\frac{-118.5}{0.0591}$

$log[H^{+}]= - 2.0051$

$[H^{+}]= 0.01M$

• The hydrogen ion concentration was calculated as $0.01M$

• The electrode potential depends on the concentration of the substances, temperature, and pressure of the substances.
• The temperature change will change the equilibrium constant.
• This will turn the concentration of the species.