Question

The electrode potential $E_{(Zn^{2+} / Zn)}$ of a zinc electrode at 25°C with an aqueous solution of 0.1 M ZnSO₄ is [$E^o_{(Zn^{2+} / Zn)}$ = -0.76 V. Assume $\frac{2.303RT}{F}$ = 0.06 at 298 K].
(a) + 0.73
(b) – 0.79
(c) – 0.82
(d) – 0.70

Answer 1

$<b>$
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→ [B]

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Answer 2

Here is your answer ⤵⤵⤵

(b)

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