Question

The electrode potentials for
Cu2+(aq)+e−→Cu+(aq)
and Cu+(aq)+e−→Cu(s)
are + 0.15 V and + 0.50 V respectively. The value of EoCu2+/Cu will be :

Answer 1

Answer:

Explanation:

Cu2+ + e- ---> Cu+ (E1° = 0.15)

Cu+ + e- ---> Cu (E2°= 0.5)

Delta G = Delta G1 + Delta G2

-nFE° = - n1FE1° + (-n2FE2°)

-2FE° = - F [ n1E1° + (n2E2°)]

2E° = n1E1° + n2E2°

2E° = 1× 0.15 + 1 × 0.5

2E° = 0.65

E° = 0.65/2

E° = 0.325

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Answer 2

Explanation:

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