The electrode potentials of four metallic elements A, B, C and D are respectively + 0.79 V, – 0.74V, + 1.08 V and –0.31V. Arrange these in order of decreasing electropositive character. Why?
Answers
"Electro positivity are also called Metallic Character.
It is defined as the "tendency of atoms" of an element to "lose electrons"and form "positive ions".
Based on the "standard electrode" "potential values" it is classified into "three categories".
"Strongly electropositive metals": Metals with a standard reduction potential close to -2.0 volts or "more negative", such as "alkaline metals", are "strongly electropositive" in nature.
"Moderately electropositive metals": Metals with reduction potential values between 0.0 and approximately -2.0 volts are moderately electropositive. This group includes Al, Zn, Fe, Ni, Co, etc.
"Weakly electropositive metals": These metals are "below hydrogen" and have positive reduction potential values. This group includes Cu, Hg, Ag, etc.
Electrode potential is the voltage that an electrode is at this has to be measured versus a reference electrode.
It is an electromotive force of a cell that has two electrodes.
From the given electrode potentials of four cells A, B, C, and D are +0.79 V, -0.74 V, +1.08 V, and -0.31 V
The order of electropositive - B > D > A > C"
Answer:
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