Question

The electrolysis of concentrated solution of sodium chloride using platinum electrodes gives


The electrolysis of concentrated solution of sodium chloride using platinum electrodes gives

Answer 1

The electrolysis of concentrated solution of sodium chloride using platinum electrodes gives gas bubbles on both anode and cathode.

hydrogen gas on negative electrode and chlorine gas on positive electrode is obtained.

hope it helps you

Answer 2

Answer: $H_{2}$ gas is liberated at cathode and $Cl_{2}$ gas is liberated at anode.

Explanation:

Electrolysis of concentrated aqueous solution of NaCl gives:

$NaCl$ → $Na^{+} (aq) + Cl^{-} (aq)$

$H_{2}O$ → $H^{+} (aq) + OH^{-} (aq)$

At cathode: Reduction takes place.

As the reduction potential of $H^{+}$ ions is more than the reduction potential of $Na^{+}$ ions, therefore reduction of  $H^{+}$ ions takes place at cathode and $H_{2}$ gas is liberated.

$2H^{+} + 2 e^{-}$ ⇆ $H_{2} (g)$

At anode: Oxidation takes place.

As the oxidation of $OH^{-}$ions requires over potential; therefore $Cl^{-}$ ions are oxidized at anode.

$2 Cl^{-}$ ⇄ $Cl_{2} (g) + 2e^{-}$

So Hydrogen is liberated at cathode and chlorine gas is liberated.

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