the electromotive force of an electric cell is 6 volt and internal resistance is 2 ohm .How many calories of heat energy would be generated by sending an electric current over 21 second by connecting an electric cell to a resistant of 8 ohm?
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Answer: First of all total resistance,
, R=internal resistance + 8 ohm resistance.
, R=2+8= 10ohms.
Now heat produced =V×I×T... (1)
Now by ohms law
I=V/R= 6/10= 3/5A...(2) ,
,Now put 2 in 1
, 6×3/5×21=H
H= 75.6J.
Explanation:
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