the electron concentration in an n-type semiconductor is the same as hole concentration in a p-type semiconductor. An external field (electric) is applyed across each of them.Compare the currents in them.
(1)current in n-type > current in p-type.
(2)No current will flow in p-type,current will only flow in n-type.
(3)current in n-type = current in p-type.
(4)current in p-type > current in n-type
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Answer (c) current in n-type > current in p-type
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the electron concentration in an n-type semiconductor is the same as hole concentration in a p-type semiconductor. An external field (electric) is applyed across each of them.
In N type semiconductor majority charge carries are e- and P type semiconductor majority charge carries are holes.
I = neAVd = neA(μE) μe > μh ⇒ Ie
Correct option is (c) current in n-type > current in p-type
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