The electron configurations of some elements are given. Based on the electron configurations, which elements can likely form ions with multiple charges?
zinc [Ar] 3d10 4s2
iron [Ar] 3d6 4s2
sodium [Ne] 3s1
cobalt [Ar] 3d7 4s2
silver [Kr] 4d10 5s1
Choose all that apply
Answers
answr is only COBALT..
rest a will have a stable configuration after losing an electron..
and iron will have a half filled d-subshell which is also very stable...
hope it's helpful...
Answer:
The arrangement of electrons in an element's atomic orbitals is described by the element's electron configuration. Atomic electron configurations follow a standard nomenclature in which the number of electrons that each atomic subshell has is listed in superscript after the order in which the electrons are found in each subshell.
Explanation:
Zinc [Ar] 3d¹⁰ 4s² = After losing two electrons, it can show only +2 oxidation state.
Iron [Ar] 3d⁶ 4s² = After losing two or three electrons, it can show +2 and +3 oxidation state.
Sodium [Ne] 3s¹ = After losing two electrons, it can show only +1 oxidation state.
Cobalt [Ar] 3d⁷ 4s² = After losing two electrons, it can show only +2 and +3 oxidation state.
Silver [Kr] 4d¹⁰ 5s¹ = After losing one electron, it can show only +1 oxidation state.
Hence, the electron configuration, in which elements can likely form ions with multiple charges are Iron [Ar] 3d⁶ 4s² and Cobalt [Ar] 3d⁷ 4s².
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