The electron in a hydrogen atom is in the n = 2 state. When it drops to the ground state a photon is emitted. What is the wavelength of the photon? please no spam
Answers
Answered by
0
Explanation:
E
2
- E
1
= -2.17 × 10
−11
[
4
1
-
1
1
] erg [ n
1
= 1, n
2
= 2]
=2.17 × 10
−11
×
4
3
erg
E
2
- E
1
= hv =
λ
c
h
λ =
ΔE
hc
=
2.17×10
−11
×3/4
6.62×10
−27
erg×3.0×10
10
cm
=
2.17
2.648
10
−5
cm
= 1.22 × 10
−5
cm = 1220A
0
Answered by
0
1 is the wavelength
Explanation:
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