Question

The electron in a hydrogen atom is in the n = 2 state. When it drops to the ground state a photon is emitted. What is the wavelength of the photon? please no spam

Answer 1

Explanation:

E

2

- E

1

= -2.17 × 10

−11

[

4

1

-

1

1

] erg [ n

1

= 1, n

2

= 2]

=2.17 × 10

−11

×

4

3

erg

E

2

- E

1

= hv =

λ

c

h

λ =

ΔE

hc

=

2.17×10

−11

×3/4

6.62×10

−27

erg×3.0×10

10

cm

=

2.17

2.648

10

−5

cm

= 1.22 × 10

−5

cm = 1220A

0

Answer 2

1 is the wavelength

Explanation: