The electron in a hydrogen atom makes a transition from n = n1 to n = n2 state. the time period of the electron in the initial state (n1) is eight times to that in the final state (n2). the possible values of n1 and n2 are
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According to the Bohr's model of hydrogen atom, the period of revolution (T) of an electron in a single electron system is directly proportional to the 3rd power of orbit number n, i.e. T is directly proportional to n³, provided that the atomic number is same for both the cases.
In the problem, it is given that T₁ = 8×T₂.
Replacing T₁ with K×n₁³, and T₂ with K×n₂³, where K is the constant of proportionality, we get n₁³ = 8×n₂³ ⇒ n₁ = 2×n₂.
So, the possible values of n₁ and n₂ are n₁ = 2,4,6,.... and n₂ = 1,2,3,....
In the problem, it is given that T₁ = 8×T₂.
Replacing T₁ with K×n₁³, and T₂ with K×n₂³, where K is the constant of proportionality, we get n₁³ = 8×n₂³ ⇒ n₁ = 2×n₂.
So, the possible values of n₁ and n₂ are n₁ = 2,4,6,.... and n₂ = 1,2,3,....
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