Question

The electron in hydrogen atom is excited to the 4th orbit number of spectral lines expected in emission is

Answer 1

Answer:

6

Explanation:

BY the spectral line formula ; n(n-1)/2

Since the atom is excited to the 4th orbit so , the value of n is 4

4(3)/2 =6

Answer 2

Given,

n=4

the formula,

$No. of spectral lines=\frac{n(n-1)}{2}$

putting value in the formula,

No. of spectral lines=  $\frac{4(4-1)}{2}$

by dividing,

No. of spectral lines = $\frac{12}{2}$

upon solving,

6.

So, the no. of spectral lines expected in emission is 6.

#SPJ2