Question

the electron in hydrogen atom is in the first Bohr's orbit (n=1) the ratio of electronic transition energies deltaE(n=1 to n=3) to deltaE(n=1 to n=2)​

Answer 1

Answer:

Consider the following two electronic transition possibilities in a hydrogen atom as pictured below:

(a) The electron drops from third Bohr orbit to second Bohr orbit followed with the next transition from second to first Bohr orbit.

(b) The electron drops from third Bohr orbit to first Bohr orbit directly. Show that the sum of energies for the transitions n=3 to n=2 and n=2 to n=1 is equal to the energy of transition for n=3 to n=1.