Question

The electron in the hydrogen atom is moving with a speed of
2.3x 106m/s in an orbit of radius 0.53A0
.Calculate the magnetic
moment of the revolving electron.

Answer 1

Explanation:

Given The electron in the hydrogen atom is moving with a speed of

2.3 x 10^6 m/s in an orbit of radius 0.53 A Calculate the magnetic  moment of the revolving electron.

• Given the electron in t he hydrogen atom is moving with a speed of 2.3 x 10^6 m / s
• So ν = 2.3 x 10^6 m / s
• Also radius = 0.53 A = 0.53 x 10^- 10 m
• Also e = 1.6 x 10^- 19 c
• So we have magnetic moment of revolving electron is given by  
• So μ = - e r ν / 2
•       = - 1.6 x 10^- 19 x 0.53 x 10^- 10 x 2.3 x 10^6 / 2
•     = - 1.95 x 10^- 23 m^2 A

Reference link will be

https://brainly.in/question/7156867