The electron in the hydrogen atom jumps from excited state (n = 3) to its ground state (n = 1)
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if we consider hν as the difference between energy En of nth excited state and ground state(n=1), we rewrite eqn.(1) as
En = eVo + φo = 10+2.75 = 12.75 eV ...................(2)
Energy difference En between nth excited state and ground state is given by, begin mathsize 12px style E subscript n space equals space 13.6 cross times open parentheses 1 minus 1 over n squared close parentheses space........................ left parenthesis 3 right parenthesis end style
from (2) and (3), we have begin mathsize 12px style 13.6 cross times open parentheses 1 minus 1 over n squared close parentheses space space equals space 12.75........................ left parenthesis 4 right parenthesis end style
solving for n in eqn.(4), we get n = 4
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