Question

The electron of energy 150ev has wavelength of 10^-10m the wavelength of a 0.60 kev electron is

Answer 1

The wavelength of 0.60 keV electron will be 0.5 x 10⁻¹⁰ m

Explanation:

We know that wavelength of an electron is given by the relation,

λ = $\frac{h}{\sqrt{2mV} }$

where,

h = planks constant

m = mass of electron

V = energy of the electron,

keeping h and m constant, we have,

λ ∝ 1/√V

=> λ₂/λ₁ = √(V₁/V₂)

=> λ₂ = 10⁻¹⁰ x √(150/600)                           ( V₂ = 0.6keV = 600 eV)

=> λ₂ = 10⁻¹⁰ x 1/2 = 0.5 x 10⁻¹⁰ m

Hence the wavelength of 0.60 keV electron will be 0.5 x 10⁻¹⁰ m

I hope this answer helps you, feel free to ask any doubt in the comment section.