Question

The electronic configuration of element X is 2, 8, 8, 1 and the electronic configuration

of element Y is 2, 8, 7. Then the type of bond formed between these two elements is

(A) covalent bond (B) hydrogen bond

(C) metallic bond (D) ionic bond​

Answer 1

Answer:

(d) ionic bond

Explanation:

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Answer 2

Answer:

Correct option is D

Ionic bond

Electronic configuration of X is 2,8,8,1. Therfore it shows metallic character.

Electronic configuration of Y is 2,8,7, shows non-metallic character.

Hence the bond formation takes place between a highly electronegative non-metal and a highly electropositve metal, thus the bond formed is an Ionic bond.

EXPLANATION :

⏩ The ionic bond is also called electrovalent bond . This bond is formed generally due to the transfer of electrons .

⏩ Covalent bonds are formed due to the sharing of electrons but ionic bonds are formed due to electron transfer .

⏩ The ionic bond is a chemical bond formed between electropositve metals and electronegative non metals .

⏩ In the given case X has an electronic configuration of 2 , 8 , 8 , 1 which means that it contains 1 valence outermost electron .

⏩ Y has an electronic configuration of 2 , 8 , 7 which means that it contains 7 outermost electrons .

⏩ We know that an atom tends to attain stable electronic configuration to its nearest noble gas . Here the element X needs to donate 1 electron to complete its octet .

⏩ On the other hand , the element Y requires to accept 1 electron so as to complete its octet ,

⏩ Thus there will be transfer of electrons from X to Y .

⏩ After the transfer X will turn into a positive univalent ion with a deficit of one electron .

⏩ Y will turn into a negative univalent ion with an excess of one electron .

⏩ The bond will be ionic bond as there is transfer of electrons in this case .