The electronic configuration of M2 ion is 2, 8, 18, 7. Determine the number of neutrons present in the
nucleus of the neutral atom. Given, mass number of the atom = 80.
Answers
Answer:
no of protons =35
no of neutrons = mass number -no of protons (or atomic number)
80-35 =45
no of neutrons =45
Given,
Electronic Configuration of M2 ion = 2,8,18,7
Mass of the atom = 80
To find,
We are required to find the number of neutrons present in the nucleus of the neutral atom.
Solution,
The number of neutrons present in the nucleus of the neutral atom is 45.
We can simply find the number of neutrons by using the formula,
Atomic mass = number of protons + number of neutrons
Number of protons = 2+8+18+7
= 35
Number of neutrons = Atomic mass - number of protons
= 80-35
= 45
Hence, the number of neutrons present in the nucleus of the neutral atom is 45.