Question

The electronic configuration of M3+ is [ Kr ] 4d10
. Its position in the periodic table is

Answer 1

Answer:

5th period group number 13

Explanation:

M3+ is [Kr] 4d10

Therefore, M = [Kr] 4d10 5s2 5p1

Here the outermost electron enters into the N−shell i.e n=5 hence the it belongs to 5th period.

The outermost electron enters into the p orbital hence it belongs to p block.

For p-block elements no. of group = (12+no of electrons in p orbital) = 12+1 = 13

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