The electronic configuration of metal 'A' is 2,8,1 and that of metal 'B' is 2,8,2. Which of the two metals is more reactive? Write their reaction with dilute hydrochloric acid.
Answers
Answer:
Explanation:
Metals 'A' Electronic configuration -(2,8,1),
Metal 'B' Electronic configuration -(2,82)
Metal 'A' loses its one electron and forms positive positive ion, but metal 'A' is more reactive than metal 'B' as metal 'B' takes more energy to remove two electrons whereas metal ''A' requires less energy to lose on the electron.
metal is sodium and metal 'B' is magnesium. Hence, sodium is more reactive than magnesium.
2NaSodium+2HClHydrochloric acid→2NaClSodium chloride+H2↑Hydrogen gas
MgMagnesium+2HClHydrochloric acid→MgCl2Magnesium Chloride→H2↑Hydrogen gas
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Answer:
On moving from left to right in a period of periodic table the chemical reactivity of elements first decreases from sodium to silicon and then increases from phosphorus to chlorine. The electronic configuration of metal 'A' is 2,8,1. This is electronic configuration of metal. In the first element of third period, sodium, there is 1 valence electron which it can loses easily to react with other substances, has 2 valence electrons. It is not easily for an atom to lose 2 electrons, so magnesium is less reactive than sodium.
Reaction with dil hydrochloric acid.
Na + HCI ➝ NaCI + H2
Mg + HCI ➝ MgCI2 + H2
Explanation:
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