Question

the electronic distribution of Mn(25)is

Answer 1

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HERE MANISH

Mn an transitional metal having 25 atomic number
have 5 balance elution in its outer most shell
electronic configuration is
1S2 2S2 2P6 3S2 3P6
3D5 4S2

it's oxidation states is
+1 +2 +3 +4 +5 +6 +7

it is the only element in first transition series with maximum oxidation state

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Answer 2

Electronic distribution of Mn (25) is $1s^{2}$$2s^{2}$$2p^{6}$$3s^{2}$$3p^{6}$$4s^{2}$$3d^{5}$

Explanation:

Manganese is a transition element and is a d block element.

the electronic configuration of Mn is $1s^{2}$$2s^{2}$$2p^{6}$$3s^{2}$$3p^{6}$$4s^{2}$$3d^{5}$

The electron enters in the d shell and 4s shell according to (n+1) rule.

The valence state can be one or more in manganese as it is a transition element.

The valence electron can be 2 of 4s2 or 7 valence electron including d orbitals.

There are 5 unpaired electrons in the d subshell of manganese.

The electron in manganese shells are written as

2,8,8,7

The d orbital electrons take part in metallic bonding.

Oxidation state of magnesium can be +2, +3, +4, +6 and +7.

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