The electronoc strictures of atoms p and q are shown.
P and q react to form an ionic compound.
what is the formula of this compound.
a) Pq2
b) P2q
c)P2Q6
d) P6Q2
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Answered by
12
Explanation:
ANSWER
Let number of atoms of Q in lattice is x
Number of tetrahedral voids =2× no. of atoms in hcp.
So number of atoms of P In lattice is 2. Hence chemical formula of the compound will be P
2x
Q
x
=P
2
Q
Answered by
15
As we see in the diagram,
The electronic configuration of P is 2,8,1.
Since only one electron is present in the outermost shell or valence shell. Hence, its valency is +1.
The electronic configuration of Q is 2,6.
Since six electrons are present in the outermost shell,
So to calculate the valency for atoms 4 or more than four we have to subtract it from 8.
So, the valency of Q should be (8−6) = 2.
So, The valency for P= +1 & Q= -2
By using cross-over valencies, we get
The chemical formula of P & Q is.
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