Question

The electronoc strictures of atoms p and q are shown.
P and q react to form an ionic compound.
what is the formula of this compound.
a) Pq2
b) P2q
c)P2Q6
d) P6Q2​

Answer 1

Explanation:

ANSWER

Let number of atoms of Q in lattice is x

Number of tetrahedral voids =2× no. of atoms in hcp.

So number of atoms of P In lattice is 2. Hence chemical formula of the compound will be P

2x

Q

x

=P

2

Q

Answer 2

As we see in the diagram,

The electronic configuration of P is 2,8,1.

Since only one electron is present in the outermost shell or valence shell. Hence, its valency is +1.

The electronic configuration of Q is 2,6.

Since six electrons are present in the outermost shell,

So to calculate the valency for atoms 4 or more than four we have to subtract it from 8.

So, the valency of Q should be (8−6) = 2.

So, The valency for P= +1 & Q= -2

By using cross-over valencies, we get

The chemical formula of P & Q is$P_2Q$.