The electrons are emitted from cathode and accelerated to anode. If the kinetic energy acquired by each electron is 6.4 x 10-16 J, then potential difference between the cathode and anode is: a) 8 x 10 V b) 1.3 x 10'y c) 2.5 x 10-V d) 4 x 10 V
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Answer:
(a)Kinectic energy of electron = eV
also, eV=
2
1
mv
2
⇒v=
2eV/m
−(1)
also, BeV=mv
2
/r
⇒r=mV/Be
using equation, (1),r=1 mm
(b)θ=30
o
v
1
=vsinθ
r
1
=mvsinθ/Be=0.5mm
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