English, asked by rajrohith164, 3 months ago

The electrons in the atoms of two elements P and Q are distributed in three

shells having 1 and 7 electrons in their outermost shells.

i) Write the group numbers in which these elements are placed in the modern

periodic table.

ii) Write the electronic configuration of P and Q and iii)the molecular formula

of

the compound formed between P and Q.​

Answers

Answered by nandini24xc
6

Answer:

In chemistry and atomic physics, an electron shell may be thought of as an orbit followed by electrons around an atom's nucleus. The closest shell to the nucleus is called the "1 shell" (also called the "K shell"), followed by the "2 shell" (or "L shell"), then the "3 shell" (or "M shell"), and so on farther and farther from the nucleus. The shells correspond to the principal quantum numbers (n = 1, 2, 3, 4 ...) or are labeled alphabetically with the letters used in X-ray notation (K, L, M, …).

Each shell can contain only a fixed number of electrons: The first shell can hold up to two electrons, the second shell can hold up to eight (2 + 6) electrons, the third shell can hold up to 18 (2 + 6 + 10) and so on. The general formula is that the nth shell can in principle hold up to 2(n2) electrons.[1] For an explanation of why electrons exist in these shells see electron configuration.[2]

Each shell consists of one or more subshells, and each subshell consists of one or more atomic orbitals.

Explanation:

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Answered by chalamsimaha
0

Explanation:

can you please send me the answer of I)

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