The electrons in the atoms of two elements P and Q are distributed in three
shells having 1 and 7 electrons in their outermost shells.
i) Write the group numbers in which these elements are placed in the modern
periodic table.
ii) Write the electronic configuration of P and Q and iii)the molecular formula
of
the compound formed between P and Q. plz write correct
Answers
Answer:
i. Element P will be placed in the first group and Element Q will be placed in the 17th group of the Modern Periodic Table.
ii. Electronic Configuration of P = 2,8,1
Electronic Configuration of Q = 2,8,7
iii. The Molecular Formula of Compound of P and Q will be PQ.
I hope this helps.
P is in Group 1 and Q is in Group 17.
Their electronic configurations are and .
The compound formed by them is NaCl.
Given:
Electrons in the third shell of P = 1
Electrons in the third shell of Q = 7
To Find:
Group numbers in which the elements are placed
Electronic configuration of P and Q
The molecular formula of the compound formed between P and Q
Solution:
Therefore as both P and Q have three shells, electrons in the first two shells = 2+8 = 10.
Electrons in the third shell of P = 1
Hence valence electrons = 1 and in s shell
Therefore P is placed in Group 1.
Q has 7 electrons in the third shell and therefore in the p shell.
Hence it is in Group 17.
The electronic configuration of P is .
The electronic configuration of Q is .
Hence P is Na, and Q is Cl.
Therefore the formula of the compound formed between P and Q is NaCl.
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