Question

The electrons in the Bohr’s orbit have
(a) K.E. greater than P.E.
(b) P.E. greater than K.E.
(c) the same values
(d) none of these

Answer 1

Answer:

(a) K.E. greater than P.E.

Explanation:

If it is correct follow me pls I 2 have the similar question it is correct I am sure

so pls follow me

Answer 2

Answer:

The electrons in the Bohr’s orbit have K.E. greater than P.E. i.e.option (a).

Explanation:

The potential energy in Bohr's orbit is given as,

$P.E=\frac{-27.2Z^2}{n}eV$      (1)

Where,

P.E=potential energy of the electron

Z=atomic number

n=quantum state in which the electron is present

The kinetic energy in Bohr's orbit is given as,

$K.E=\frac{13.6Z^2}{n}eV$        (2)

K.E=kinetic energy associated with the electron in nth Bohr's orbit

By comparing equations (1) and (2) we can see that the kinetic energy is greater than the potential energy.

Hence, the correct answer among the given option is (a)i.e. K.E. greater than P.E.