The electrons in the hydrogen atom jumps from
excited state (n = 3) to its ground state
(n = 1) and the photons thus emitted irradiate a
photosensitive material. If the work function of
the material is 5.1 eV, the stopping potential is
estimated to be the energy of the electron in nth
state E =-eV)
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2
Answer:
Energy released when electron in the atom jumps from excited state (n=3) to ground state (n=1) is
E=hν=E
3
−E
1
=
3
2
−13.6
−(
1
2
−13.6
)=
9
−13.6
+13.6=12.1 eV
Therefore, stopping potential: eV
0
=hν−ϕ
0
=12.1−5.1 [∵ work function ϕ
0
=5.1]
⇒V
0
=7V
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