The electrostatic energy of Z protons uniformly distributed throughout
a spherical nucleus of radius R is given by E = 3/5 Z(Z-1) e²/ 4????????₀R
The measured masses of the neutron, ¹₁H, ¹⁵₇N and ¹⁵₈O are 1.008665 u, 1.007825 u, 15.000109 u and
15.003065u, respectively. Given that the radii of both the ¹⁵₇N and ¹⁵₈O nuclei are same, 1 u = 931.5
MeV/c² ( c is the speed of light) and e²/(4????????₀R) = 1.44 MeV fm. Assuming that the difference between the
binding energies of ¹⁵₇N and ¹⁵₈O is purely due to the electrostatic energy, the radius of either of the nuclei
is
(1 fm = 10⁻¹⁵m)
(A) 2.85 fm (B) 3.03 fm
(C) 3.42 fm (D) 3.80 fm
Answers
Answered by
1
Answer:
I think its answer is option
B)3.03
Answered by
2
Answer is
C) 3.42 fm
Hopefully understandable ^-^
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