Physics, asked by arunsaroha6495, 10 months ago

The electrostatic energy of Z protons uniformly distributed throughout
a spherical nucleus of radius R is given by E = 3/5 Z(Z-1) e²/ 4????????₀R
The measured masses of the neutron, ¹₁H, ¹⁵₇N and ¹⁵₈O are 1.008665 u, 1.007825 u, 15.000109 u and
15.003065u, respectively. Given that the radii of both the ¹⁵₇N and ¹⁵₈O nuclei are same, 1 u = 931.5
MeV/c² ( c is the speed of light) and e²/(4????????₀R) = 1.44 MeV fm. Assuming that the difference between the
binding energies of ¹⁵₇N and ¹⁵₈O is purely due to the electrostatic energy, the radius of either of the nuclei
is
(1 fm = 10⁻¹⁵m)
(A) 2.85 fm (B) 3.03 fm
(C) 3.42 fm (D) 3.80 fm

Answers

Answered by royniraj17
1

Answer:

I think its answer is option

B)3.03

Answered by yusufyunus
2

Answer is

C) 3.42 fm

Hopefully understandable ^-^

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