The electrostatic force between two
charges of one coulomb each and placed
at a distance of 0.5 m will be
(a) 36 x 106
(6) 36-x 107N
(c) 36 x 108 N
(d) 36 x 10°N
Answers
Answered by
1
Answer:
Answer is 36 *10^9N sorry for not uploading explanation.
Answered by
0
Explanation:
F=1/4π€0[q1q2/r²]
F=9×10^9[1×1/(0.5)²]
F=9×10^9/0.25
F=9×10^9/25/100
F=9×10^11/25
F=0.36×10^11
F=36×10^9N is the correct answer
hope this helps you
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