Question

The electrostatic force of between two positively charged ions carrying equal charge is 3.7x10^-9 N , when the are separated by a distance of 5x10^-10 . How many electrons are missing from each ion?

Answer 1

given-
F= 3.7x10^-9 N
r = 5 x 10^-10 m
K =Coulomb's law constant = 9 x 10^9 Nm^2/C^2

so
F = (K x q^2) / r^2
q^2 = {(3.7 x 10^-9) x (25 x 10^-20)} / ( 9 x 10^9)
q^2 = 10.278 x 10^-38
q = 3.2 x 10^-19 C

and 
q= ne
3.2 x 10^-19 = n x 1.6 x 10^-19
so n = 2 electrons are missing from each ion

i hope it will help you 
regards

Answer 2

Answer:2

Explanation is done in beneath the