Question

The electrostatic force of repulsion between two positively charged ions carrying equal charges = 3.7 x 10-9n when they are separated by a distance of 5 å. how many electrons are missing from each ion? [

Answer 1

given charge (q)
then
n=q/e
we need to find 'n'
=>n=3. 7×10-9÷1. 6×10-19
=>n=2. 312× 10 (10)

Answer 2

Answer:

Explanation:

given charge (q)

then

n=q/e

we need to find 'n'

=>n=3. 7×10-9÷1. 6×10-19

=>n=2. 312× 10 (10)