The electrostatic potential energy of two point charges 1 microcoulomb each place 1 m apart in vacuum is
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Electrostatic potential energy , U = KQ₁Q₂/r
Here, Q₁ = Q₂ = 1μC = 10⁻⁶C and r = 1m
So, Potential energy = 9 × 10⁹ × 10⁻⁶ × 10⁻⁶/(1)²
= 9 × 10⁹ × 10⁻¹² Joules
= 9 × 10⁻³ Joules
Hence, electrostatic potential energy is 9 × 10⁻³ J or 0.009J
Here, Q₁ = Q₂ = 1μC = 10⁻⁶C and r = 1m
So, Potential energy = 9 × 10⁹ × 10⁻⁶ × 10⁻⁶/(1)²
= 9 × 10⁹ × 10⁻¹² Joules
= 9 × 10⁻³ Joules
Hence, electrostatic potential energy is 9 × 10⁻³ J or 0.009J
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