Chemistry, asked by raksha1801, 9 months ago

The element aluminium is written by the symbol 2713AL1327AL.write the number of protons,electrons and neutrons present in it.

Answers

Answered by jaskaransahi20060
7

Explanation:

Aluminium-27 is an isotope of aluminium characterized by the fact that is has a mass number equal to 27.

Now, an atom's mass number tells you the total number of protons and of neutrons that atom has in its nucleus. Since you're dealing with an isotope of aluminium, it follows that this atom must have the exact same number of protons in its nucleus.

The number of protons an atom has in its nucleus is given by the atomic number. A quick looks in the periodic table will show that aluminium has an atomic number equal to 13.

This means that any atom that is an isotope of aluminium will have 13 protons in its nucleus.

Since you're dealing with a neutral atom, the number of electrons that surround the nucleus must be equal to the number of protons found in the nucleus.

Therefore, the aluminium-27 isotope will have 13 electrons surrounding its nucleus.

Finally, use the known mass number to determine how many neutrons you have

mass number=no. of protons+no. of neutrons

no. of neutrons=27−13=14

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