Question

THE ELEMENT With Electronic configuration (Ne) 3s2 3p6,3d1,4s2 belongs to ------------

Answer 1

Ca is the right answer and it's belong to alkali metal 1(A) group hope it's help.....

Answer 2

Electronic configuration → [Ne] 3s² 3p⁶ 3d¹ 4s²

Due to electronegativity difference, the last electron enters the 3d subshell and hence the element belongs to the d-block.

• Electronic configuration → [Ne] 3s² 3p⁶ 3d¹ 4s²
• Total electrons = 21
• Atomic Number = 21
• Element → Scandium (Sc)
• In light of the fact that the orbitals of the 3d have much greater energy than those of the 4s, the orbitals of the 4s fill up first since they have lower energy.
• The elements in which the valence electrons enter the d subshell, are present in the d-block.

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