Question

The elements A,B and C have the atomic numbers 12,16 and 20
respectively..which two will show similar properties.Give reason

Answer 1

Solution :

⏭ Given:

✏ Atomic numbers of elements A, B and C are respectively 12, 16 and 20.

⏭ To Find:

✏ Which two will show similar properties.

⏭ Concept:

✏ In modern periodic table elements of same group contain same physical and chemical properties.

⏭ Electronic configuration:

$\mapsto \sf \: _{12}A = \red{ [Ne] 3 {s}^{2} }\\ \\ \mapsto \sf \: _{16}B = \blue{ [Ne] 3 {s}^{2} 3 {p}^{4} }\\ \\ \mapsto \sf \: _{20}C = \green{[Ar] 4 {s}^{2} }$

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$\implies \sf \: Group \: no. \: of \: A = \red{2} \\ \\ \implies \sf \: Group \: no. \: of \: B = \blue{16} \\ \\ \implies \sf \: Group \: no. \: of \: C = \green{2}$

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$\leadsto \sf \: A \: and \: C \: are \: the \: elements \: of \: same \: group. \\ \\ \bigstar \: \underline{ \boxed{ \bold{ \sf{ \orange{ \large{Answer = A \: and \: C}}}}}} \: \bigstar$