Biology, asked by ashwinkaursethi, 1 year ago

The elements of the second periodic table are:Li,Be,B,C,N,O,F. i)Give reasons to explain why atomic radii decrease from Li to F. ii) identity the most a) metallic and b) non metallic elements.

Answers

Answered by Anonymous

1)As the tendency to gain electron increases left to right in a period ..free electrons are not present in outermost shell..so the shells are close to each other
2)a)most metallic is Li (left side of the periodic table)
b)non metallic F (right side in a period)

Anonymous: which std are u in?

Raj021: I am curruntly in class 10 th

Anonymous: see...the effective nuclear charge increases so ..it holds the shells near to its nucleus which gives them a small atomic radii

Raj021: thanks.

Anonymous: have u been taught effective nuclear charge?

Raj021: only a little about it.

Anonymous: yaa this force is exerted by nucleus

Anonymous: to orbitals

Raj021: thanks

Anonymous: welcome

Answered by Raj021

the atomic radius decreases from left to right in a period as the no. of valance electrons increase the force of the protons in the nucleus increases leading to more attraction force to electrons.This reduces the size of atom
1: the most metallic element in second period is Li
2: the most non metallic element is F.

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