The elements undergoing reduction and oxidation during the reaction
(NH4)2Cr2O7------>N2 + Cr2O3 + 4H20 are respectively
(A) N and Cr
(8) Cr and N
(C) N and o
(D) Cr and o
Answers
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Explanation:
NH
4
)
2
Cr
2
O
7
⟶N
2
+Cr
2
O
3
+4H
2
O
2N
3−
−6e
−
⟶2N
0
(Oxidation)
2Cr
VI
+6e
−
⟶2Cr
III
(Reduction
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