Question

The elements x=32% y=24% z=44% The relative number of atoms of x,y and z are 2,1 and 0.5 respectively. Find the atomic masses of element x,y,z.

Answer 1

Answer:

Explanation:

Molecular mass of the compound = 400 g/mol

Percentage of of element x = 32%

The relative number of atoms of x, y and z are 2, 1 and 0.5, respectively.

Empirical formula of the compound :

Molecular formula of the compound =

Percentage of of element x = 32%

Percentage of of element y = 24%

Percentage of of element z = 44 %

Empirical mass of the compound :

Empirical mass = molecular mass = 400 g/mol

So, the molecular formula will also empirical formula .