Physics, asked by varadacharya2901, 4 months ago

The Elephant weighs 40,000 N stands on one foot of area 2000 cm2. How much pressure would it exert on the ground

Answers

Answered by Nurulthesir
0

Answer:

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Answered by Anonymous
2

Answer:

Weight of elephant=40000N

Area of one foot = 1000 cm

2

=1000×10

−4

m

2

Weight of girl=400N

Area of heel of girl = 1 cm

2

=1×10

−4

m

2

(a) Elephant has a larger weight of 40000N, therefore, elephant exerts a larger force on the ground. Elephant exerts a larger force on the ground by 40000N - 400 N = 39600 N.

(b) Weight of elephant = 40000N

Area of one foot = 1000 cm

2

=1000×10

−4

m

2

Pressure=

Area

Force

Pressure=

1000×10

−4

40000

=400000N/m

2

(c) Weight of the girl = 400N

Area of heel of girl =1 cm

2

=1×10

−4

m

2

Pressure=

Area

Force

Pressure=

1×10

−4

400

=4000000N/m

2

(d) Girl exerts a larger pressure on the ground.

(e) Ratio =

Pressure exerted by the elephant

Pressure exerted by the girl

=

400000

4000000

=

1

10

The pressure exerted by girl is 10 times greater than that exerted by the elephant

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