Question

The elevation of a tower at a station A due north of it is a and at a station B due west of A is B.
Prove that the height of the tower is
ABsina sinß
sin?a- sin2 B
​

Yeash
Seawar

U^ｪ^U ​

Answer 1

Answer:

∴PA=hcotα

and h=PBtanβ 

∴PB=hcotβ

Also from the right-angled triangle PAB, we get

PB2=PA2+AB2

∴AB2=PB2−PA2

=h2(cot2β−cot2α)

∴h=(cot2β−cot2α)AB

h=tan2α−tan2βABtanαtanβ

Substituitng,  tanα=cosαsinα

Or ,

h=(sin2αcos2β−cos2αsin2β)

Explanation:

HOPE this ANSWER will HELP you

Answer 2

Thankyou Vansh

Now I got answer to my on the spot Declaration today !