# The elevator descends at the rate of 5 m/min .if the descent starts from 50 m above the ground level,find the time taken by the elevator to reach -250 m.

## Answers

Answered by

4

**Answer:**

Subtract 50 and 250 and put the sign finally divide with 5

**Step-by-step explanation:**

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Answered by

19

**Answer:**

60 min =1 hour

**Step-by-step explanation:**

ATQ => total distance elevator has travel =

initial position = Final position

50 - (-250)

50+250

=300 m

NOW,

Elevator descends at the rate of =5m / min

elevator travel 5m in = 1 minute

elevator travel 1m in = 1/5 minute

elevator travel 300 m in = 1/5 × 300

= 60 min = 1hours

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