The elevator descends at the rate of 5 m/min .if the descent starts from 50 m above the ground level,find the time taken by the elevator to reach -250 m.
Answers
Answered by
4
Answer:
Subtract 50 and 250 and put the sign finally divide with 5
Step-by-step explanation:
Iam anonymous don't like me but I can help you bye bro
Answered by
19
Answer:
60 min =1 hour
Step-by-step explanation:
ATQ => total distance elevator has travel =
initial position = Final position
50 - (-250)
50+250
=300 m
NOW,
Elevator descends at the rate of =5m / min
elevator travel 5m in = 1 minute
elevator travel 1m in = 1/5 minute
elevator travel 300 m in = 1/5 × 300
= 60 min = 1hours
Similar questions