The elevator descends at the rate of 5m/ Mon. If the descent stars from 50 m above the ground level, find the time taken by the elevator to reach - 250 m???
Answers
Initial height = 50m
Final depth = -250m
Here we took the final depth as negative because the elevator is descending ( going down)
Total height descent by the elevator
= 50- (-250)
= 300m
As the elevator descends at 5m/min
Time taken by the elevator to descend 5m = 1 minute
Time taken by the elevator to descend 1m = 1/5 min
Therefore:-
Time taken by elevator to descend -300m
=
60min = 1hour.
Therefore:-
Time taken by elevator to reach - 250m is 1 hour.
Initial height = 50m
Final depth = -250m
Here we took the final depth as negative because the elevator is descending ( going down)
Total height descent by the elevator
= 50- (-250)
= 300m
As the elevator descends at 5m/min
Time taken by the elevator to descend 5m = 1 minute
Time taken by the elevator to descend 1m = 1/5 min
Therefore:-
Time taken by elevator to descend -300m
= \sf \dfrac{ 300}{ 5}5300
60min = 1hour.
Therefore:-
Time taken by elevator to reach - 250m is 1 hour.
Explanation: