Question

The elevator descends at the rate of 5m/ Mon. If the descent stars from 50 m above the ground level, find the time taken by the elevator to reach - 250 m?????​

Answer 1

Initial height = 50m

Final depth = -250m

Here we took the final depth as negative because the elevator is descending ( going down)

Total height descent by the elevator

= 50- (-250)

= 300m

As the elevator descends at 5m/min

Time taken by the elevator to descend 5m = 1 minute

Time taken by the elevator to descend 1m = 1/5 min

Therefore:-

Time taken by elevator to descend -300m

= 300/5

60min = 1hour.

Therefore:-

Time taken by elevator to reach - 250m is 1 hour.

Answer 2

Answer:

Explanation:

Final depth = -250m

Here we took the final depth as negative because the elevator is descending ( going down)

Total height descent by the elevator

= 50- (-250)

= 300m

As the elevator descends at 5m/min

Time taken by the elevator to descend 5m = 1 minute

Time taken by the elevator to descend 1m = 1/5 min

Therefore:-

Time taken by elevator to descend -300m

$= \sf \dfrac{ 300}{ 5}$

60min = 1hour.

Therefore:-

Time taken by elevator to reach - 250m is 1 hour.