Question

The elevator shown in figure (5−E5) is descending with an acceleration of 2 m/s2. The mass of the block A is 0.5 kg. What force is exerted by the block A on the block B?

Figure

Answer 1

Answer:

The force exerted by the block A on the block B is 4 N.

Explanation:

When the elevator is descending, a pseudo-force acts on it in the upward direction .

From the free-body diagram of block A,

mg-N=ma

N=m(g-a)

⇒N=0.5(10-2)

=4 N

So, the force exerted by the block A on the block B is 4 N.

Answer 2

Answer:

The force exerted by the block A on the block B is 4 N.

Explanation:

When the elevator is descending, a pseudo-force acts on it in the upward direction .

From the free-body diagram of block A,

mg-N=ma

N=m(g-a)

⇒N=0.5(10-2)

=4 N

So, the force exerted by the block A on the block B is 4 N.