The elevator shown in figure (5−E5) is descending with an acceleration of 2 m/s2. The mass of the block A is 0.5 kg. What force is exerted by the block A on the block B?
Figure
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Answer:
The force exerted by the block A on the block B is 4 N.
Explanation:
When the elevator is descending, a pseudo-force acts on it in the upward direction .
From the free-body diagram of block A,
mg-N=ma
N=m(g-a)
⇒N=0.5(10-2)
=4 N
So, the force exerted by the block A on the block B is 4 N.
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1
Answer:
The force exerted by the block A on the block B is 4 N.
Explanation:
When the elevator is descending, a pseudo-force acts on it in the upward direction .
From the free-body diagram of block A,
mg-N=ma
N=m(g-a)
⇒N=0.5(10-2)
=4 N
So, the force exerted by the block A on the block B is 4 N.
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