Question

The elevator shown in figure is descending with an
acceleration of 2 ms. The mass of the block A =
0.5 kg. The force exerted by the block A on the
block B is :
2ms-2
(a) 2 N (b) 4 N(C)
N (d) 8 N​

Answer 1

Answer:

b option is correct.........

Answer 2

Force on block B due to A,$N_{B} = 0.2(9 - 2) = 1.4$ Newton.

Explanation:

We make the FBD for A block and go through the attached photo.

Pseudo force :- it is also called as fictitious force, inertial force or d'Alembert force and it is an apparent force that acts on all masses whose motion is described using a non-inertial frame of reference frame.

So the equation will be

$N_{B} + \textrm{Psuedo force} = mass \time \textrm{gravitational acceleration}$

$N_{B} + ma = mg$

$N_{B} = m(g - a)$

$N_{B} = 0.2(9 - 2) = 1.4$ Newton.