the elongation of bar is 0.5 mm when a tensile stress 200n/mm2 determine original length of bar if modulas of elasticity is 150 ×10 raised to 3?
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the original length of the bar is 365 mm or 0.365 m
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Answer:
answer 375mm
Explanation:
GIVEN:
change in length =0.5
tensile stress 200n/mm2
modulas of elasticity is 150 ×10raised to 3
young's modulus (E) =stress/strain
strain = (change in length/original length)
= 0.5/L
therefore young's modulus (E)= (200 ×L)/0.5
150000 = 400L
L= 150000/400
L=375mm
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