The elongation of spring is 1 cm and its potentialenergy is u. If the spring is elongated by 3cm thepotential energy will be
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Answer...
PE of spring ,
U = ½kx²
u = ½k(1)² = ½k ...... (1)
u' = ½k(3)² = ½k(9).......(2)
comparing equation 1 & 2 ,
u' = 9u
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