Question

The emf (in V) of a Daniel cell containing 0.1M ZnSo4, and 0.01M Cuso4, solutions at their
respective electrodes is (E°Cu+2/Cu = +0.34V) (E° Zn+2/zn =-0.76V)​

Answer 1

Answer:

1.07volt

Explanation:

here n=2

E(standard cell)=0.34-(-0.76)=0.34+0.76=1.1

therefore,

E(cell)=1.1-0.0591/2*log10

=1.1-0.02955

=1.07volt