Question

The EMF of a cell is 5.0 V . When it is connected across a resistor of 4.5 Ω , the potential drop across the resistor is found to be 3.0 V . Calculate the internal resistance of the cell.​

Answer 1

Relation between all Values given and asked:-

iR=E-ir-----------------(1)

The value of iR is given as 3V

iR=3V---------------------------------(2)

i=3/R----------------------------------(3)

Putting the values in 1

3=5-3r/R

2=3r/R

Hence r = 3Ω

Final answer

3Ω

Answer 2

Answer:

your answer in the attachment

Explanation:

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