Question

The emf of a cell is balanced by a length of 150 cm of potentiometer wire. When the

cell is shunted by a resistance of 6 Ω, the balancing length is reduced by 50 cm. Find

the internal resistance of the cell.
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Answer 1

Answer:

r = 12Ω

Explanation:

internal resistance( r )=( L1/L2-1)R

given :-

L1 = 150 cm

L2 = 50 cm

shunt resistance R = 6Ω

r =(150/50 -1)×6

r =(3-1)×6

r =2×6

r = 12Ω